Integrand size = 35, antiderivative size = 283 \[ \int \frac {A+B \sin (e+f x)}{(a+a \sin (e+f x)) (c+d \sin (e+f x))^3} \, dx=-\frac {\left (3 A d \left (2 c^2+2 c d+d^2\right )-B \left (2 c^3+4 c^2 d+7 c d^2+2 d^3\right )\right ) \arctan \left (\frac {d+c \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c^2-d^2}}\right )}{a (c-d) \left (c^2-d^2\right )^{5/2} f}-\frac {d (2 A c-3 B c+3 A d-2 B d) \cos (e+f x)}{2 a (c-d)^2 (c+d) f (c+d \sin (e+f x))^2}-\frac {(A-B) \cos (e+f x)}{(c-d) f (a+a \sin (e+f x)) (c+d \sin (e+f x))^2}-\frac {d \left (2 A c^2-5 B c^2+9 A c d-6 B c d+4 A d^2-4 B d^2\right ) \cos (e+f x)}{2 a (c-d)^3 (c+d)^2 f (c+d \sin (e+f x))} \]
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Time = 0.38 (sec) , antiderivative size = 283, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.171, Rules used = {3057, 2833, 12, 2739, 632, 210} \[ \int \frac {A+B \sin (e+f x)}{(a+a \sin (e+f x)) (c+d \sin (e+f x))^3} \, dx=-\frac {\left (3 A d \left (2 c^2+2 c d+d^2\right )-B \left (2 c^3+4 c^2 d+7 c d^2+2 d^3\right )\right ) \arctan \left (\frac {c \tan \left (\frac {1}{2} (e+f x)\right )+d}{\sqrt {c^2-d^2}}\right )}{a f (c-d) \left (c^2-d^2\right )^{5/2}}-\frac {d \left (2 A c^2+9 A c d+4 A d^2-5 B c^2-6 B c d-4 B d^2\right ) \cos (e+f x)}{2 a f (c-d)^3 (c+d)^2 (c+d \sin (e+f x))}-\frac {d (2 A c+3 A d-3 B c-2 B d) \cos (e+f x)}{2 a f (c-d)^2 (c+d) (c+d \sin (e+f x))^2}-\frac {(A-B) \cos (e+f x)}{f (c-d) (a \sin (e+f x)+a) (c+d \sin (e+f x))^2} \]
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Rule 12
Rule 210
Rule 632
Rule 2739
Rule 2833
Rule 3057
Rubi steps \begin{align*} \text {integral}& = -\frac {(A-B) \cos (e+f x)}{(c-d) f (a+a \sin (e+f x)) (c+d \sin (e+f x))^2}-\frac {\int \frac {a (3 A d-B (c+2 d))-2 a (A-B) d \sin (e+f x)}{(c+d \sin (e+f x))^3} \, dx}{a^2 (c-d)} \\ & = -\frac {d (2 A c-3 B c+3 A d-2 B d) \cos (e+f x)}{2 a (c-d)^2 (c+d) f (c+d \sin (e+f x))^2}-\frac {(A-B) \cos (e+f x)}{(c-d) f (a+a \sin (e+f x)) (c+d \sin (e+f x))^2}+\frac {\int \frac {-2 a \left (2 (A-B) d^2+c (3 A d-B (c+2 d))\right )+a d (2 A c-3 B c+3 A d-2 B d) \sin (e+f x)}{(c+d \sin (e+f x))^2} \, dx}{2 a^2 (c-d)^2 (c+d)} \\ & = -\frac {d (2 A c-3 B c+3 A d-2 B d) \cos (e+f x)}{2 a (c-d)^2 (c+d) f (c+d \sin (e+f x))^2}-\frac {(A-B) \cos (e+f x)}{(c-d) f (a+a \sin (e+f x)) (c+d \sin (e+f x))^2}-\frac {d \left (2 A c^2-5 B c^2+9 A c d-6 B c d+4 A d^2-4 B d^2\right ) \cos (e+f x)}{2 a (c-d)^3 (c+d)^2 f (c+d \sin (e+f x))}-\frac {\int \frac {a \left (3 A d \left (2 c^2+2 c d+d^2\right )-B \left (2 c^3+4 c^2 d+7 c d^2+2 d^3\right )\right )}{c+d \sin (e+f x)} \, dx}{2 a^2 (c-d)^3 (c+d)^2} \\ & = -\frac {d (2 A c-3 B c+3 A d-2 B d) \cos (e+f x)}{2 a (c-d)^2 (c+d) f (c+d \sin (e+f x))^2}-\frac {(A-B) \cos (e+f x)}{(c-d) f (a+a \sin (e+f x)) (c+d \sin (e+f x))^2}-\frac {d \left (2 A c^2-5 B c^2+9 A c d-6 B c d+4 A d^2-4 B d^2\right ) \cos (e+f x)}{2 a (c-d)^3 (c+d)^2 f (c+d \sin (e+f x))}-\frac {\left (3 A d \left (2 c^2+2 c d+d^2\right )-B \left (2 c^3+4 c^2 d+7 c d^2+2 d^3\right )\right ) \int \frac {1}{c+d \sin (e+f x)} \, dx}{2 a (c-d)^3 (c+d)^2} \\ & = -\frac {d (2 A c-3 B c+3 A d-2 B d) \cos (e+f x)}{2 a (c-d)^2 (c+d) f (c+d \sin (e+f x))^2}-\frac {(A-B) \cos (e+f x)}{(c-d) f (a+a \sin (e+f x)) (c+d \sin (e+f x))^2}-\frac {d \left (2 A c^2-5 B c^2+9 A c d-6 B c d+4 A d^2-4 B d^2\right ) \cos (e+f x)}{2 a (c-d)^3 (c+d)^2 f (c+d \sin (e+f x))}-\frac {\left (3 A d \left (2 c^2+2 c d+d^2\right )-B \left (2 c^3+4 c^2 d+7 c d^2+2 d^3\right )\right ) \text {Subst}\left (\int \frac {1}{c+2 d x+c x^2} \, dx,x,\tan \left (\frac {1}{2} (e+f x)\right )\right )}{a (c-d)^3 (c+d)^2 f} \\ & = -\frac {d (2 A c-3 B c+3 A d-2 B d) \cos (e+f x)}{2 a (c-d)^2 (c+d) f (c+d \sin (e+f x))^2}-\frac {(A-B) \cos (e+f x)}{(c-d) f (a+a \sin (e+f x)) (c+d \sin (e+f x))^2}-\frac {d \left (2 A c^2-5 B c^2+9 A c d-6 B c d+4 A d^2-4 B d^2\right ) \cos (e+f x)}{2 a (c-d)^3 (c+d)^2 f (c+d \sin (e+f x))}+\frac {\left (2 \left (3 A d \left (2 c^2+2 c d+d^2\right )-B \left (2 c^3+4 c^2 d+7 c d^2+2 d^3\right )\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (c^2-d^2\right )-x^2} \, dx,x,2 d+2 c \tan \left (\frac {1}{2} (e+f x)\right )\right )}{a (c-d)^3 (c+d)^2 f} \\ & = -\frac {\left (3 A d \left (2 c^2+2 c d+d^2\right )-B \left (2 c^3+4 c^2 d+7 c d^2+2 d^3\right )\right ) \arctan \left (\frac {d+c \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c^2-d^2}}\right )}{a (c-d)^3 (c+d)^2 \sqrt {c^2-d^2} f}-\frac {d (2 A c-3 B c+3 A d-2 B d) \cos (e+f x)}{2 a (c-d)^2 (c+d) f (c+d \sin (e+f x))^2}-\frac {(A-B) \cos (e+f x)}{(c-d) f (a+a \sin (e+f x)) (c+d \sin (e+f x))^2}-\frac {d \left (2 A c^2-5 B c^2+9 A c d-6 B c d+4 A d^2-4 B d^2\right ) \cos (e+f x)}{2 a (c-d)^3 (c+d)^2 f (c+d \sin (e+f x))} \\ \end{align*}
Time = 3.28 (sec) , antiderivative size = 313, normalized size of antiderivative = 1.11 \[ \int \frac {A+B \sin (e+f x)}{(a+a \sin (e+f x)) (c+d \sin (e+f x))^3} \, dx=\frac {\left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right ) \left (4 (A-B) \sin \left (\frac {1}{2} (e+f x)\right )+\frac {2 \left (-3 A d \left (2 c^2+2 c d+d^2\right )+B \left (2 c^3+4 c^2 d+7 c d^2+2 d^3\right )\right ) \arctan \left (\frac {d+c \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c^2-d^2}}\right ) \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )}{(c+d)^2 \sqrt {c^2-d^2}}+\frac {(c-d) d (B c-A d) \cos (e+f x) \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )}{(c+d) (c+d \sin (e+f x))^2}+\frac {d \left (-A d (5 c+2 d)+B \left (3 c^2+2 c d+2 d^2\right )\right ) \cos (e+f x) \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )}{(c+d)^2 (c+d \sin (e+f x))}\right )}{2 a (c-d)^3 f (1+\sin (e+f x))} \]
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Time = 2.49 (sec) , antiderivative size = 482, normalized size of antiderivative = 1.70
method | result | size |
derivativedivides | \(\frac {-\frac {2 \left (\frac {\frac {d^{2} \left (7 c^{2} d A +2 d^{2} c A -2 A \,d^{3}-5 B \,c^{3}-2 c^{2} d B \right ) \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2 c \left (c^{2}+2 c d +d^{2}\right )}+\frac {d \left (6 A \,c^{4} d +2 A \,c^{3} d^{2}+11 A \,c^{2} d^{3}+4 A c \,d^{4}-2 A \,d^{5}-4 B \,c^{5}-2 B \,c^{4} d -9 B \,c^{3} d^{2}-4 B \,c^{2} d^{3}-2 B c \,d^{4}\right ) \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2 \left (c^{2}+2 c d +d^{2}\right ) c^{2}}+\frac {d^{2} \left (17 c^{2} d A +6 d^{2} c A -2 A \,d^{3}-11 B \,c^{3}-6 c^{2} d B -4 d^{2} c B \right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{2 c \left (c^{2}+2 c d +d^{2}\right )}+\frac {d \left (6 c^{2} d A +2 d^{2} c A -A \,d^{3}-4 B \,c^{3}-2 c^{2} d B -d^{2} c B \right )}{2 c^{2}+4 c d +2 d^{2}}}{{\left (\left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right ) c +2 d \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+c \right )}^{2}}+\frac {\left (6 c^{2} d A +6 d^{2} c A +3 A \,d^{3}-2 B \,c^{3}-4 c^{2} d B -7 d^{2} c B -2 d^{3} B \right ) \arctan \left (\frac {2 c \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+2 d}{2 \sqrt {c^{2}-d^{2}}}\right )}{2 \left (c^{2}+2 c d +d^{2}\right ) \sqrt {c^{2}-d^{2}}}\right )}{\left (c -d \right )^{3}}-\frac {2 \left (A -B \right )}{\left (c -d \right )^{3} \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )}}{a f}\) | \(482\) |
default | \(\frac {-\frac {2 \left (\frac {\frac {d^{2} \left (7 c^{2} d A +2 d^{2} c A -2 A \,d^{3}-5 B \,c^{3}-2 c^{2} d B \right ) \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2 c \left (c^{2}+2 c d +d^{2}\right )}+\frac {d \left (6 A \,c^{4} d +2 A \,c^{3} d^{2}+11 A \,c^{2} d^{3}+4 A c \,d^{4}-2 A \,d^{5}-4 B \,c^{5}-2 B \,c^{4} d -9 B \,c^{3} d^{2}-4 B \,c^{2} d^{3}-2 B c \,d^{4}\right ) \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2 \left (c^{2}+2 c d +d^{2}\right ) c^{2}}+\frac {d^{2} \left (17 c^{2} d A +6 d^{2} c A -2 A \,d^{3}-11 B \,c^{3}-6 c^{2} d B -4 d^{2} c B \right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{2 c \left (c^{2}+2 c d +d^{2}\right )}+\frac {d \left (6 c^{2} d A +2 d^{2} c A -A \,d^{3}-4 B \,c^{3}-2 c^{2} d B -d^{2} c B \right )}{2 c^{2}+4 c d +2 d^{2}}}{{\left (\left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right ) c +2 d \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+c \right )}^{2}}+\frac {\left (6 c^{2} d A +6 d^{2} c A +3 A \,d^{3}-2 B \,c^{3}-4 c^{2} d B -7 d^{2} c B -2 d^{3} B \right ) \arctan \left (\frac {2 c \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+2 d}{2 \sqrt {c^{2}-d^{2}}}\right )}{2 \left (c^{2}+2 c d +d^{2}\right ) \sqrt {c^{2}-d^{2}}}\right )}{\left (c -d \right )^{3}}-\frac {2 \left (A -B \right )}{\left (c -d \right )^{3} \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )}}{a f}\) | \(482\) |
risch | \(\text {Expression too large to display}\) | \(1881\) |
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Leaf count of result is larger than twice the leaf count of optimal. 1608 vs. \(2 (274) = 548\).
Time = 0.37 (sec) , antiderivative size = 3303, normalized size of antiderivative = 11.67 \[ \int \frac {A+B \sin (e+f x)}{(a+a \sin (e+f x)) (c+d \sin (e+f x))^3} \, dx=\text {Too large to display} \]
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Timed out. \[ \int \frac {A+B \sin (e+f x)}{(a+a \sin (e+f x)) (c+d \sin (e+f x))^3} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {A+B \sin (e+f x)}{(a+a \sin (e+f x)) (c+d \sin (e+f x))^3} \, dx=\text {Exception raised: ValueError} \]
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Leaf count of result is larger than twice the leaf count of optimal. 727 vs. \(2 (274) = 548\).
Time = 0.38 (sec) , antiderivative size = 727, normalized size of antiderivative = 2.57 \[ \int \frac {A+B \sin (e+f x)}{(a+a \sin (e+f x)) (c+d \sin (e+f x))^3} \, dx=\frac {\frac {{\left (2 \, B c^{3} - 6 \, A c^{2} d + 4 \, B c^{2} d - 6 \, A c d^{2} + 7 \, B c d^{2} - 3 \, A d^{3} + 2 \, B d^{3}\right )} {\left (\pi \left \lfloor \frac {f x + e}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (c\right ) + \arctan \left (\frac {c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + d}{\sqrt {c^{2} - d^{2}}}\right )\right )}}{{\left (a c^{5} - a c^{4} d - 2 \, a c^{3} d^{2} + 2 \, a c^{2} d^{3} + a c d^{4} - a d^{5}\right )} \sqrt {c^{2} - d^{2}}} - \frac {2 \, {\left (A - B\right )}}{{\left (a c^{3} - 3 \, a c^{2} d + 3 \, a c d^{2} - a d^{3}\right )} {\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 1\right )}} + \frac {5 \, B c^{4} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} - 7 \, A c^{3} d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 2 \, B c^{3} d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} - 2 \, A c^{2} d^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 2 \, A c d^{5} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 4 \, B c^{5} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 6 \, A c^{4} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 2 \, B c^{4} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 2 \, A c^{3} d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 9 \, B c^{3} d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 11 \, A c^{2} d^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 4 \, B c^{2} d^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 4 \, A c d^{5} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 2 \, B c d^{5} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 2 \, A d^{6} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 11 \, B c^{4} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 17 \, A c^{3} d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 6 \, B c^{3} d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 6 \, A c^{2} d^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 4 \, B c^{2} d^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 2 \, A c d^{5} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 4 \, B c^{5} d - 6 \, A c^{4} d^{2} + 2 \, B c^{4} d^{2} - 2 \, A c^{3} d^{3} + B c^{3} d^{3} + A c^{2} d^{4}}{{\left (a c^{7} - a c^{6} d - 2 \, a c^{5} d^{2} + 2 \, a c^{4} d^{3} + a c^{3} d^{4} - a c^{2} d^{5}\right )} {\left (c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 2 \, d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + c\right )}^{2}}}{f} \]
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Time = 17.95 (sec) , antiderivative size = 1076, normalized size of antiderivative = 3.80 \[ \int \frac {A+B \sin (e+f x)}{(a+a \sin (e+f x)) (c+d \sin (e+f x))^3} \, dx=\frac {\frac {A\,d^4-2\,A\,c^4+2\,B\,c^4-8\,A\,c^2\,d^2+4\,B\,c^2\,d^2-2\,A\,c\,d^3-4\,A\,c^3\,d+B\,c\,d^3+8\,B\,c^3\,d}{\left (c+d\right )\,\left (c^2-d^2\right )\,\left (c^2-2\,c\,d+d^2\right )}-\frac {{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,\left (2\,A\,d^6-13\,A\,c^2\,d^4-17\,A\,c^3\,d^3-22\,A\,c^4\,d^2+4\,B\,c^2\,d^4+19\,B\,c^3\,d^3+23\,B\,c^4\,d^2-2\,A\,c\,d^5-8\,A\,c^5\,d+2\,B\,c\,d^5+12\,B\,c^5\,d\right )}{c^2\,\left (c^2-2\,c\,d+d^2\right )\,\left (-c^3-c^2\,d+c\,d^2+d^3\right )}+\frac {{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,\left (2\,A\,d^5-4\,A\,c^5+4\,B\,c^5-21\,A\,c^2\,d^3-14\,A\,c^3\,d^2+14\,B\,c^2\,d^3+17\,B\,c^3\,d^2-4\,A\,c\,d^4-4\,A\,c^4\,d+2\,B\,c\,d^4+8\,B\,c^4\,d\right )}{c^2\,\left (c^2-d^2\right )\,\left (c^2-2\,c\,d+d^2\right )}+\frac {{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4\,\left (2\,A\,c^5-2\,A\,d^5-2\,B\,c^5+7\,A\,c^2\,d^3+2\,A\,c^3\,d^2-2\,B\,c^2\,d^3-7\,B\,c^3\,d^2+2\,A\,c\,d^4+4\,A\,c^4\,d-4\,B\,c^4\,d\right )}{c\,\left (c^2-2\,c\,d+d^2\right )\,\left (-c^3-c^2\,d+c\,d^2+d^3\right )}+\frac {\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (2\,A\,d^5-27\,A\,c^2\,d^3-22\,A\,c^3\,d^2+15\,B\,c^2\,d^3+29\,B\,c^3\,d^2-5\,A\,c\,d^4-8\,A\,c^4\,d+4\,B\,c\,d^4+12\,B\,c^4\,d\right )}{c\,\left (c+d\right )\,\left (c^2-d^2\right )\,\left (c^2-2\,c\,d+d^2\right )}}{f\,\left ({\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,\left (2\,a\,c^2+4\,a\,c\,d+4\,a\,d^2\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,\left (2\,a\,c^2+4\,a\,c\,d+4\,a\,d^2\right )+a\,c^2+\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (a\,c^2+4\,a\,d\,c\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4\,\left (a\,c^2+4\,a\,d\,c\right )+a\,c^2\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5\right )}-\frac {\mathrm {atan}\left (\frac {\frac {\left (-2\,a\,c^5\,d+2\,a\,c^4\,d^2+4\,a\,c^3\,d^3-4\,a\,c^2\,d^4-2\,a\,c\,d^5+2\,a\,d^6\right )\,\left (2\,B\,c^3-3\,A\,d^3+2\,B\,d^3-6\,A\,c\,d^2-6\,A\,c^2\,d+7\,B\,c\,d^2+4\,B\,c^2\,d\right )}{2\,a\,{\left (c+d\right )}^{5/2}\,{\left (c-d\right )}^{7/2}}-\frac {c\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (a\,c^5-a\,c^4\,d-2\,a\,c^3\,d^2+2\,a\,c^2\,d^3+a\,c\,d^4-a\,d^5\right )\,\left (2\,B\,c^3-3\,A\,d^3+2\,B\,d^3-6\,A\,c\,d^2-6\,A\,c^2\,d+7\,B\,c\,d^2+4\,B\,c^2\,d\right )}{a\,{\left (c+d\right )}^{5/2}\,{\left (c-d\right )}^{7/2}}}{2\,B\,c^3-3\,A\,d^3+2\,B\,d^3-6\,A\,c\,d^2-6\,A\,c^2\,d+7\,B\,c\,d^2+4\,B\,c^2\,d}\right )\,\left (2\,B\,c^3-3\,A\,d^3+2\,B\,d^3-6\,A\,c\,d^2-6\,A\,c^2\,d+7\,B\,c\,d^2+4\,B\,c^2\,d\right )}{a\,f\,{\left (c+d\right )}^{5/2}\,{\left (c-d\right )}^{7/2}} \]
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